tube.c

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/*= -*- c-basic-offset: 4; indent-tabs-mode: nil; -*-
 *
 * librsync -- dynamic caching and delta update in HTTP
 *
 * Copyright (C) 2000, 2001 by Martin Pool <mbp@sourcefrog.net>
 *
 * This program is free software; you can redistribute it and/or modify
 * it under the terms of the GNU Lesser General Public License as published by
 * the Free Software Foundation; either version 2.1 of the License, or
 * (at your option) any later version.
 *
 * This program is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
 * GNU Lesser General Public License for more details.
 *
 * You should have received a copy of the GNU Lesser General Public License
 * along with this program; if not, write to the Free Software
 * Foundation, Inc., 675 Mass Ave, Cambridge, MA 02139, USA.
 */
 
                              /*=
                               | Where a calculator on the ENIAC is
                               | equpped with 18,000 vaccuum tubes and
                               | weighs 30 tons, computers in the
                               | future may have only 1,000 vaccuum
                               | tubes and perhaps weigh 1 1/2
                               | tons.
                               |   -- Popular Mechanics, March 1949
                               */
 
/** \file tube.c
 * A somewhat elastic but fairly small buffer for data passing through a
 * stream.
 *
 * In most cases the iter can adjust to send just as much data will fit. In
 * some cases that would be too complicated, because it has to transmit an
 * integer or something similar. So in that case we stick whatever won't fit
 * into a small buffer.
 *
 * A tube can contain some literal data to go out (typically command bytes),
 * and also an instruction to copy data from the stream's input or from some
 * other location. Both literal data and a copy command can be queued at the
 * same time, but only in that order and at most one of each.
 *
 * \todo As an optimization, write it directly to the stream if possible. But
 * for simplicity don't do that yet.
 *
 * \todo I think our current copy code will lock up if the application only
 * ever calls us with either input or output buffers, and not both. So I guess
 * in that case we might need to copy into some temporary buffer space, and
 * then back out again later. */
 
#include "config.h"             /* IWYU pragma: keep */
#include <assert.h>
#include <stdlib.h>
#include <string.h>
#include "librsync.h"
#include "job.h"
#include "scoop.h"
#include "trace.h"
 
static void rs_tube_catchup_write(rs_job_t *job)
{
    rs_buffers_t *stream = job->stream;
    size_t len = job->write_len;
 
    assert(len > 0);
    if (len > stream->avail_out)
        len = stream->avail_out;
    if (len) {
        memcpy(stream->next_out, job->write_buf, len);
        stream->next_out += len;
        stream->avail_out -= len;
        job->write_len -= len;
        if (job->write_len > 0)
            /* Still something left in the tube, shuffle it to the front. */
            memmove(job->write_buf, job->write_buf + len, job->write_len);
    }
    rs_trace("wrote " FMT_SIZE " bytes from tube, " FMT_SIZE " left to write",
             len, job->write_len);
}
 
/** Catch up on an outstanding copy command.
 *
 * Takes data from the scoop and writes as much as will fit to the output, up
 * to the limit of the outstanding copy. */
static void rs_tube_catchup_copy(rs_job_t *job)
{
    assert(job->write_len == 0);
    assert(job->copy_len > 0);
    rs_buffers_t *stream = job->stream;
    size_t copy_len = job->copy_len;
    size_t avail_in = rs_scoop_avail(job);
    size_t avail_out = stream->avail_out;
    size_t len, ilen;
    void *next;
 
    if (copy_len > avail_in)
        copy_len = avail_in;
    if (copy_len > avail_out)
        copy_len = avail_out;
    len = copy_len;
    for (next = rs_scoop_iterbuf(job, &len, &ilen); ilen > 0;
         next = rs_scoop_nextbuf(job, &len, &ilen)) {
        memcpy(stream->next_out, next, ilen);
        stream->next_out += ilen;
        stream->avail_out -= ilen;
        job->copy_len -= ilen;
    }
    rs_trace("copied " FMT_SIZE " bytes from scoop, " FMT_SIZE
             " left in scoop, " FMT_SIZE " left to copy", copy_len,
             rs_scoop_avail(job), job->copy_len);
}
 
/** Put whatever will fit from the tube into the output of the stream.
 *
 * \return RS_DONE if the tube is now empty and ready to accept another
 * command, RS_BLOCKED if there is still stuff waiting to go out. */
rs_result rs_tube_catchup(rs_job_t *job)
{
    if (job->write_len) {
        rs_tube_catchup_write(job);
        if (job->write_len)
            return RS_BLOCKED;
    }
 
    if (job->copy_len) {
        rs_tube_catchup_copy(job);
        if (job->copy_len) {
            if (rs_scoop_eof(job)) {
                rs_error("reached end of file while copying data");
                return RS_INPUT_ENDED;
            }
            return RS_BLOCKED;
        }
    }
    return RS_DONE;
}
 
/* Check whether there is data in the tube waiting to go out.
 
   \return true if the previous command has finished doing all its output. */
int rs_tube_is_idle(rs_job_t const *job)
{
    return job->write_len == 0 && job->copy_len == 0;
}
 
/** Queue up a request to copy through \p len bytes from the input to the
 * output of the stream.
 *
 * The data is copied from the scoop (if there is anything there) or from the
 * input, on the next call to rs_tube_write().
 *
 * We can only accept this request if there is no copy command already pending.
 *
 * \todo Try to do the copy immediately, and return a result. Then, people can
 * try to continue if possible. Is this really required? Callers can just go
 * out and back in again after flushing the tube. */
void rs_tube_copy(rs_job_t *job, size_t len)
{
    assert(job->copy_len == 0);
 
    job->copy_len = len;
}
 
/** Push some data into the tube for storage.
 *
 * The tube's never supposed to get very big, so this will just pop loudly if
 * you do that.
 *
 * We can't accept write data if there's already a copy command in the tube,
 * because the write data comes out first. */
void rs_tube_write(rs_job_t *job, const void *buf, size_t len)
{
    assert(job->copy_len == 0);
    assert(len <= sizeof(job->write_buf) - job->write_len);
 
    memcpy(job->write_buf + job->write_len, buf, len);
    job->write_len += len;
}